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say hello world with C++ - Solution in Hacker Rank - hackerranksolutions8

  Objective This is a simple challenge to help you practice printing to  stdout . You may also want to complete  Solve Me First  in C++ before attempting this challenge. We’re starting out by printing the most famous computing phrase of all time! In the editor below, use either  printf  or  cout  to print the string  Hello ,World!  to  stdout . The more popular command form is  cout . It has the following basic form: cout<<value_to_print<<value_to_print; Any number of values can be printed using one command as shown. The  printf  command comes from C language. It accepts an optional format specification and a list of variables. Two examples for printing a string are: printf("%s", string);   printf(string); Note that neither method adds a newline. It only prints what you tell it to. Output Format Print   Hello ,World!   to stdout. Sample Output Hello, World! Solution:- //Say Hello, ...
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Digit Frequency in C Hackerrank Solution

 Given a string, s , consisting of alphabets and digits, find the frequency of each digit in the given string.

Input Format

The first line contains a string, num which is the given number.

Constraints

1 < len(num) < 1000

All the elements of num are made of english alphabets and digits.

Output Format

Print ten space-separated integers in a single line denoting the frequency of each digit from 0 to 9.

Sample Input 0

a11472o5t6

Sample Output 0

0 2 1 0 1 1 1 1 0 0

Explanation 0

In the given string:

  •  1 occurs two times.
  •  2, 4, 5, 6 and 7 occur one time each.
  • The remaining digits 0, 3, 8 and 9 don’t occur at all.

Sample Input 1

lw4n88j12n1

Sample Output 1

0 2 1 0 1 0 0 0 2 0

Sample Input 2

1v88886l256338ar0ekk

Sample Output 2

1 1 1 2 0 1 2 0 5 0

Code

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
  
    char *s;
    s = malloc(1024 * sizeof(char));
    scanf("%s", s);
    s = realloc(s, strlen(s) + 1);
    int len = strlen(s), i;
    int arr[10];
    for(i = 0; i < 10; i++)
        arr[i] = 0;
    for(i = 0; i < len; i++) {
        if(s[i] >= '0' && s[i] <= '9') {
            arr[(int)(s[i] - '0')]++;
        }
    }
    for(i = 0; i < 10; i++)
        printf("%d ", arr[i]);
    printf("\n");
    free(s);
    return 0;
}

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