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say hello world with C++ - Solution in Hacker Rank - hackerranksolutions8

  Objective This is a simple challenge to help you practice printing to  stdout . You may also want to complete  Solve Me First  in C++ before attempting this challenge. We’re starting out by printing the most famous computing phrase of all time! In the editor below, use either  printf  or  cout  to print the string  Hello ,World!  to  stdout . The more popular command form is  cout . It has the following basic form: cout<<value_to_print<<value_to_print; Any number of values can be printed using one command as shown. The  printf  command comes from C language. It accepts an optional format specification and a list of variables. Two examples for printing a string are: printf("%s", string);   printf(string); Note that neither method adds a newline. It only prints what you tell it to. Output Format Print   Hello ,World!   to stdout. Sample Output Hello, World! Solution:- //Say Hello, ...
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FOR LOOP IN C in C Hackerrank Solution

 Objective

In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be repeatedly executed.

The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>
  • expression_1 is used for intializing variables which are generally used for controlling the terminating flag for the loop.
  • expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
  • expression_3 is generally used to update the flags/variables.

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Task

For each integer n in the interval [a,b] (given as input) :

  • If  1 < n < 9, then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
  • Else if n > 9 and it is an even number, then print “even”.
  • Else if n > 9 and it is an odd number, then print “odd”.

Input Format

The first line contains an integer, a.
The seond line contains an integer,b .

Constraints

1 < a < b < 106

Output Format

Print the appropriate english representation,even, or odd, based on the conditions described in the ‘task’ section.

Note: [a,b]={x ∈ Z | a < x < b } = {a,a+1,……,b}

Sample Input

8
11

Sample Output

eight
nine
even
odd

Code:

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() 
{
    int a, b,n;
    scanf("%d\n%d", &a, &b);
  	// Complete the code.
    for(n=a;n<=b;n++)
    {
     if(n==1)
        printf("one\n");
    else if(n==2)
        printf("two\n");
    else if(n==3)
        printf("three\n");
    else if(n==4)
        printf("four\n");
    else if(n==5)
        printf("five\n");
    else if(n==6)
        printf("six\n");
    else if(n==7)
        printf("seven\n");
    else if(n==8)
        printf("eight\n");
    else if(n==9)
        printf("nine\n");
    else if(n>9)
    {

        if(n%2==0)
        printf("even\n");
        else {
            printf("odd\n");
        }
    }
    }
    return 0;
}

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