Java Datatypes – Hacker Rank Solution

 Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we’ll work with the primitives used to hold integer values (byte, short, int, and long):

• A byte is an 8-bit signed integer.
• A short is a 16-bit signed integer.
• An int is a 32-bit signed integer.
• A long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input.

To get you started, a portion of the solution is provided for you in the editor.

Reference: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Input Format

The first line contains an integer,T , denoting the number of test cases.
Each test case, T  , is comprised of a single line with an integer,n , which can be arbitrarily large or small.

Output Format

For each input variable n  and appropriate primitive datatype, you must determine if the given primitives are capable of storing it. If yes, then print:

n can be fitted in:
* dataType

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.: ).

byte < short < int < long

If the number cannot be stored in one of the four aforementioned primitives, print the line:

n can't be fitted anywhere.

Sample Input

5
-150
150000
1500000000
213333333333333333333333333333333333
-100000000000000

Sample Output

-150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long

Explanation

 -150 can be stored in a short, an int, or a long.

 213333333333333333333333333333333333is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.

Solution:-

// Java Datatypes - Beatthecode Solution
import java.util.*;
import java.io.*;

class Solution{
    public static void main(String []argh)
    {

        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();

        for(int i=0;i<t;i++)
        {

            try
            {
                long x = sc.nextLong();
                
                // Java Datatypes - HackerRank Solution START
                
                System.out.println(x+" can be fitted in:");
                if(x>=-128 && x<=127)
                {
                    System.out.println("* byte");
                }
                if(x>=-32768 && x<=32767)
                {
                    System.out.println("* short");
                }
                if(x>=-2147483648 && x<=2147483647)
                {
                    System.out.println("* int");
                }
                System.out.println("* long");
                
                // Java Datatypes - HackerRank Solution END
            }
            catch(Exception e)
            {
                System.out.println(sc.next()+" can't be fitted anywhere.");
            }

        }
    }
}