Java Strings Introduction hackerrank solution

 “A string is traditionally a sequence of characters, either as a literal constant or as some kind of variable.” — Wikipedia: String (computer science)

This exercise is to test your understanding of Java Strings. A sample String declaration:

String myString = "Hello World!"

The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.

Given two strings of lowercase English letters, A  and B , perform the following operations:

1. Sum the lengths of A  and B .
2. Determine if A is lexicographically larger than B  (i.e.: does B  come before A in the dictionary?).
3. Capitalize the first letter in A and B   and print them on a single line, separated by a space.

Input Format

The first line contains a string  A . The second line contains another string  B . The strings are comprised of only lowercase English letters.

Output Format

There are three lines of output:
For the first line, sum the lengths of   A and  B .
For the second line, write Yes if  A  is lexicographically greater than  B  otherwise print No instead.
For the third line, capitalize the first letter in both  A  and  B  and print them on a single line, separated by a space.

Sample Input 0

hello
java

Sample Output 0

9
No
Hello Java

Explanation 0

String  A  is “hello” and  B  is “java”.

  A has a length of 5, and  B  has a length of 4; the sum of their lengths is 9.
When sorted alphabetically/lexicographically, “hello” precedes “java”; therefore,  A  is not greater than  B  and the answer is No.

When you capitalize the first letter of both  A  and  B  and then print them separated by a space, you get “Hello Java”.

Solution:-

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        
        Scanner sc=new Scanner(System.in);
String A=sc.next();
String B=sc.next();
System.out.println(A.length()+B.length());
System.out.println(A.compareTo(B)>0?"Yes":"No");
System.out.println(A.substring(0, 1).toUpperCase()+A.substring(1, A.length())+" "+B.substring(0, 1).toUpperCase()+B.substring(1, B.length()));
        
    }
}