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say hello world with C++ - Solution in Hacker Rank - hackerranksolutions8

  Objective This is a simple challenge to help you practice printing to  stdout . You may also want to complete  Solve Me First  in C++ before attempting this challenge. We’re starting out by printing the most famous computing phrase of all time! In the editor below, use either  printf  or  cout  to print the string  Hello ,World!  to  stdout . The more popular command form is  cout . It has the following basic form: cout<<value_to_print<<value_to_print; Any number of values can be printed using one command as shown. The  printf  command comes from C language. It accepts an optional format specification and a list of variables. Two examples for printing a string are: printf("%s", string);   printf(string); Note that neither method adds a newline. It only prints what you tell it to. Output Format Print   Hello ,World!   to stdout. Sample Output Hello, World! Solution:- //Say Hello, ...
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Pattern Syntax Checker Hacker Rank Solution in Java

 Problem:-

Using Regex, we can easily match or search for patterns in a text. Before searching for a pattern, we have to specify one using some well-defined syntax.In this problem, you are given a pattern. You have to check whether the syntax of the given pattern is valid.

Note: 

In this problem, a regex is only valid if you can compile it using the Pattern.compile method.

Input Format

The first line of input contains an integer , denoting the number of test cases. The next  lines contain a string of any printable characters representing the pattern of a regex

Output Format

For each test case, print Valid if the syntax of the given pattern is correct. Otherwise, print Invalid. Do not print the quotes.

Sample Input

3
([A-Z])(.+)
[AZ[a-z](a-z)
batcatpat(nat

Sample Output

Valid
Invalid
Invalid

Solution:-

import java.util.Scanner;


import java.util.regex.*;



public class Solution


{


    public static void main(String[] args){


        Scanner in = new Scanner(System.in);


        int testCases = Integer.parseInt(in.nextLine());


        while(testCases > 0){


            String pattern = in.nextLine();


            try {


                Pattern.compile(pattern);


                System.out.println("Valid");


            } catch (PatternSyntaxException e) {


                System.out.println("Invalid");


            }


            testCases--;


        }


    }


}

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