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say hello world with C++ - Solution in Hacker Rank - hackerranksolutions8

  Objective This is a simple challenge to help you practice printing to  stdout . You may also want to complete  Solve Me First  in C++ before attempting this challenge. We’re starting out by printing the most famous computing phrase of all time! In the editor below, use either  printf  or  cout  to print the string  Hello ,World!  to  stdout . The more popular command form is  cout . It has the following basic form: cout<<value_to_print<<value_to_print; Any number of values can be printed using one command as shown. The  printf  command comes from C language. It accepts an optional format specification and a list of variables. Two examples for printing a string are: printf("%s", string);   printf(string); Note that neither method adds a newline. It only prints what you tell it to. Output Format Print   Hello ,World!   to stdout. Sample Output Hello, World! Solution:- //Say Hello, ...

Sum and Difference between Two Numbers in C Hackerrank solution

 Objective

The fundamental data types in c are int, float and char. Today, we’re discussing int and float data types.

The printf() function prints the given statement to the console. The syntax is printf("format string",argument_list);. In the function, if we are using an integer, character, string or float as argument, then in the format string we have to write %d (integer), %c (character), %s (string), %f (float) respectively.

The scanf() function reads the input data from the console. The syntax is scanf("format string",argument_list);. For ex: The scanf("%d",&number) statement reads integer number from the console and stores the given value in variable number.

To input two integers separated by a space on a single line, the command is scanf("%d %d", &n, &m), where n and m are the two integers.

Task

Your task is to take two numbers of int data type, two numbers of float data type as input and output their sum:

  1. Declare 4 variables: two of type int and two of type float.
  2. Read 2  lines of input from stdin (according to the sequence given in the ‘Input Format’ section below) and initialize your 4  variables.
  3. Use the + and – operator to perform the following operations:
    • Print the sum and difference of two int variable on a new line.
    • Print the sum and difference of two float variable rounded to one decimal place on a new line.

Input Format

The first line contains two integers.
The second line contains two floating point numbers.

Constraints

  • 1< integer variables<=10^4 
  •  1<float variables<=10^4 

Output Format

Print the sum and difference of both integers separated by a space on the first line, and the sum and difference of both float (scaled to 1 decimal place) separated by a space on the second line.

Sample Input

10 4
4.0 2.0

Sample Output

14 6
6.0 2.0

Explanation

When we sum the integers 10 and 4 , we get the integer . When we subtract the second number 4 from the first number 10, we get 6 as their difference.
When we sum the floating-point numbers 4.0 and 2.0 , we get 6.0 . When we subtract the second number 2.0 from the first number 4.0 , we get 2.0 as their difference.

Code:

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main()
{
    int n1,n2;
    float n3,n4;
	scanf("%d %d\n",&n1,&n2);
    scanf("%f %f\n",&n3,&n4);
    printf("%d %d\n",n1+n2,n1-n2);
    printf("%.1f %.1f",n3+n4,n3-n4);
    return 0;
}

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