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say hello world with C++ - Solution in Hacker Rank - hackerranksolutions8

  Objective This is a simple challenge to help you practice printing to  stdout . You may also want to complete  Solve Me First  in C++ before attempting this challenge. We’re starting out by printing the most famous computing phrase of all time! In the editor below, use either  printf  or  cout  to print the string  Hello ,World!  to  stdout . The more popular command form is  cout . It has the following basic form: cout<<value_to_print<<value_to_print; Any number of values can be printed using one command as shown. The  printf  command comes from C language. It accepts an optional format specification and a list of variables. Two examples for printing a string are: printf("%s", string);   printf(string); Note that neither method adds a newline. It only prints what you tell it to. Output Format Print   Hello ,World!   to stdout. Sample Output Hello, World! Solution:- //Say Hello, ...

Maps-STL in C++ – Solution in Hacker Rank - hackerranksolutions8

 

Problem

Maps are a part of the C++ STL.Maps are associative containers that store elements formed by a combination of a key value and a mapped value, following a specific order. The mainly used member functions of maps are:

Map Template:

std::map <key_type, data_type>

Declaration:

map<string,int>m; //Creates a map m where key_type is of type string and data_type is of type int.

Size:

int length=m.size(); //Gives the size of the map.

Insert:

m.insert(make_pair("hello",9)); //Here the pair is inserted into the map where the key is "hello" and the value associated with it is 9.

Erasing an element:

m.erase(val); //Erases the pair from the map where the key_type is val.

Finding an element:

map<string,int>::iterator itr=m.find(val); //Gives the iterator to the element val if it is found otherwise returns m.end() .
Ex: map<string,int>::iterator itr=m.find("Maps"); //If Maps is not present as the key value then itr==m.end().

Accessing the value stored in the key:

To get the value stored of the key "MAPS" we can do m["MAPS"] or we can get the iterator using the find function and then by itr->second we can access the value.

To know more about maps click Here.
You are appointed as the assistant to a teacher in a school and she is correcting the answer sheets of the students.Each student can have multiple answer sheets.So the teacher has Q queries:

  1. X Y : Add the marks Y to the student whose name is X.
  2. X : Erase the marks of the student whose name is X.
  3. X : print the marks of the student whose name is X. (if X didn’t get any marks print 0. )

Input Format :

The first line of the input contains Q where Q is the number of queries. The next Q lines contain 1 query each.The first integer, type of each query is the type of the query. If query is of type 1, it consists of one string and an integer X and Y where X is the name of the student and Y is the marks of the student. If query is of type 2 or 3, it consists of a single string X where X is the name of the student.

Constraints :

  • 1 <= Q <= 10^5
  • 1 <= type <= 3
  • 1 <= |X| <= 6
  • 1 <= Y <= 10^3

Output Format :

For queries of type 3 print the marks of the given student.


Sample Input :

7
1 Jesse 20
1 Jess 12
1 Jess 18
3 Jess
3 Jesse
2 Jess
3 Jess

Sample Output :

30
20
0

Solution :

//Maps-STL in C++ - Hacker Rank Solution
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <set>
#include <map>
#include <algorithm>
using namespace std;


int main() 
{
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 
    /*Maps-STL in C++ - Hacker Rank Solution START */  
    map <string,int> m;
    int N = 0;
    cin >> N;
    for (int i = 0; i < N; i++)
    {
        int q = 0;
        cin>>q;
        string x;
        if (q == 1)
        {
            int y = 0;
            cin>>x;
            cin>>y;
            m[x] += y;
        }
        else if (q == 2)
        {
            cin>>x;
            m.erase(x);
        }
        else
        {
            cin>>x;
            map<string,int>::iterator itr=m.find(x);
            if (itr != m.end())
                cout<<m[x]<<endl;
            else
                cout<<0<<endl;
        }
    }
    /* Maps-STL in C++ - Hacker Rank Solution END */
    return 0;
}

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