Strings in C++ – Solution in Hacker Rank - hackerranksolutions8

 

Problem

C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:
Declaration:

string a = "abc";

Size:

int len = a.size();

Concatenate two strings:

string a = "abc";
string b = "def";
string c = a + b; // c = "abcdef".

Accessing i th element:

string s = "abc";
char   c0 = s[0];   // c0 = 'a'
char   c1 = s[1];   // c1 = 'b'
char   c2 = s[2];   // c2 = 'c'

s[0] = 'z';         // s = "zbc"

P.S.: We will use cin/cout to read/write a string.

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Input Format

You are given two strings, a and b, separated by a new line. Each string will consist of lower case Latin characters (‘a’-‘z’).

Output Format

In the first line print two space-separated integers, representing the length of a and b, respectively.In the second line print the string produced by concatenating a and b(a+b).In the third line print two strings separated by a space, a’ and b’.a’ and b’ are the same as a and b, respectively, except that their first characters are swapped.

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Sample Input :

abcd
ef

Sample Output :

4 2
abcdef
ebcd af

Explanation :

• a  = “abcd”
• b  = “ef”
• |a| = 4
• |b| = 2
• a+b = “abcdef”
• a’ = “ebcd”
• b’ = “af”

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Solution :- 

#include <iostream>
#include <string>
using namespace std;

int main() 
{
    string str1,str2,str3;
    char b,a;
    int strlen1,strlen2;
    //string one 
    cin>>str1;
    //string two
      cin>>str2;
    
    //first string size
    strlen1 = str1.size();
    //second string size
    strlen2 = str2.size();
    cout<<strlen1;
    cout<<" "<<strlen2;
    
    // concatinate two string
    str3 = str1+str2;
    cout<<"\n"<<str3;
    
    // a' b'
    a = str2[0];
    b = str1[0];        
    str1[0] = a;
    str2[0] = b;
    cout<<"\n";
    cout<<str1;
    cout<<" "<<str2;
    return 0;
}